[Lab] Odd Question
Michael
krazatchu at hotmail.com
Fri Jan 20 15:35:44 EST 2012
Other things to consider that may effect combustion...
100 C is likely the vapor flash point within a narrow air:fuel ratio.
Submersion in vegetable oil would probably keep the oxygen out but...
A mixture will have entirely different properties depending on the
components.
Other reactions besides oxygen + fuel could occur or be catalyzed by
heat + electricity...
For example chlorine is a strong oxidizer, a candle will readily burn in it.
Have fun!
Michael
http://n0m1.com/
http://krazatchu.ca/
On 1/20/2012 3:15 PM, Emily Daniels wrote:
> Wow! Thank you for that deduction Michael! That is way better than I
> could have ever done. Inside the cell will be sealed off from air but
> the outside top is exposed, unless I seal that off too. Ideally the
> thing will fluoresce and emit a steady glow from the energy generated
> from the oscillations in the Rochelle and Epsom salts with even a 1.5
> or 3 volt battery, 9 volt is the highest I'd like to go. Guess I'll
> find out...
>
> On Fri, Jan 20, 2012 at 3:00 PM, Michael <krazatchu at hotmail.com
> <mailto:krazatchu at hotmail.com>> wrote:
>
> This is a interesting challenge..
>
> The supply droop with resistive load will be a factor of the
> batteries internal resistance.
> Which is an effect of temperature, chemistry and state of charge.
>
> Internal resistance can be measured by subjecting the battery to a
> known load ...
> http://en.wikipedia.org/wiki/Internal_resistance
> Then applying (Nominal V - Loaded V) * (Load R) / (Nominal V)
> Or you can just figure it's about 0.2 Ohms per Alkaline cell.
> A 9V is sometimes made of 6 cells, so about 1.2 Ohms.
>
> Once you have the internal resistance figured...
> The circuit is a 9v voltage source with two series resistances,
> internal + load.
> The voltage drop over the internal resistance will be 9 - 6 = 3v
> and using i = V/R we get the current over the internal resitance...
> i = 3/1.2 = 2.5 Amps (there's going to be some serious self
> heating which will skew the results)
>
> As the circuit is series, the current thru the internal resistance
> is the same as the current thru the load...
> And the final voltage drop over the unknown load is the remainder,
> 6 volts. Using R = V/i...
> R = 6 / 2.5 = 2.4 Ohms ...
>
> Finally heat is a factor of power dissipation...
> Power is V*i = 6 * 2.5 = 15 Watts...
>
> I just tested this with a Rayovac 9v and a 2.7 ohm load...
> The results were a bit off, the internal resitance of the rayovac
> must be higher than 1.2 ohms
> I got a supply drop to 3.4 volts and a 1.15 amps current.
> Using the above calculation, the rayovac has an internal
> resistance of 1.73 ohms..
> So we could probably guess between 10 to 12 watts of power lost
> into load...
>
> Temperature rise is a factor of thermal conductivity and geometry...
> I'd guess that the sugar cell has a pretty low thermal
> conductivity and that 10 watts could heat a sugar cell to over
> 100c given enough time..
> Combustion is going to require an oxidizer so YMMV....
>
> Michael
> http://n0m1.com/
> http://krazatchu.ca/
>
>
>
> On 1/20/2012 1:49 PM, Darcy Whyte wrote:
>>
>> I suppose if you can try it on a couple and see what the current
>> is, then you can know how many Watts. That would be a start. Then
>> you just have to figure out how much of the heat is in the load
>> and how much is in the battery. You can probably do that by
>> knowing the resistance of the load.
>>
>>
>>
>>
>> On Fri, Jan 20, 2012 at 1:33 PM, Emily Daniels
>> <emily.daniels at gmail.com <mailto:emily.daniels at gmail.com>> wrote:
>>
>> Hi All,
>>
>> Does anyone know how much heat is produced by a 9 volt
>> battery when the resistance of the material it flows through
>> reduces it to 6 volts? What would the temperature be inside
>> the material? Thanks!
>>
>> Emily
>>
>> --
>> Emily Daniels | emilydaniels.com <http://emilydaniels.com> |
>> @emdaniels | awesomefoundation.org <http://awesomefoundation.org>
>>
>>
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> Emily Daniels | emilydaniels.com <http://emilydaniels.com> |
> @emdaniels | awesomefoundation.org <http://awesomefoundation.org>
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